IDNStudy.com, ang iyong gabay para sa maaasahan at mabilis na mga sagot. Magtanong ng anumang bagay at makatanggap ng agarang tugon mula sa aming dedikadong komunidad ng mga eksperto.
Answer:
The value of y in the following proportion,
[tex]a. \frac{y}{21}=\frac{28}{49} \\ 49y=28(21)\\ 49y=588\\ \frac{49y}{49} =\frac{588}{49\\ }\\ y= 12\\\\ b.\frac{y+5}{12} =\frac{9}{4\\ } \\ 4(y+5)= 9(12)\\ 4y +20=108\\ 4y+20-20=108-20\\ 4y=88\\ \frac{4y}{4} = \frac{88}{4} \\ y=22\\ \\ c.\frac{y+4}{6}=\frac{7y}{3}\\ 3(y+4)=7y(6)\\ 3y+12=42y\\3y-3y+12=42y-3y \\ 12=39y\\ \frac{39y}{39} =\frac{12}{39} \\ y=\frac{12}{39} or4/13\\ \\ d.\frac{2y-3}{3}=\frac{3y-7}{2} \\ 2(2y-3)=3(3y-7)\\ 4y-6=9y-21\\ 4y-6+6=9y-21+6\\ 4y=9y-15\\ 4y-9y=9y-9y-15\\ -5y=-15\\ y=3[/tex]
#CarryOnLearning
-Pantonal