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A taxi running at 30 m/s slowed down uniformly until it stopped in 44 s when a passenger signalled to it. Find the acceleration and the stopping distance.

Sagot :

A taxi running at 30 m/s slowed down uniformly until it stopped in 44 s when a passenger signalled to it. Find the acceleration and the stopping distance.

Distance:1320 meters

Acceleration:1.14m/s²

Solution

Distance formula Time × speed

30×44=1320

Acceleration formula=Vi-Vf÷T

Solution=

=(0-30)÷44

=1.14

1.14m/s²