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Answer:
4/9
Step-by-step explanation:
P(A) = Probability that team A wins the volleyball competition = (1 / 3)
P(B) = Probability that team B wins the volleyball competition = (1 / 9)
P(C) = Probability that team C wins the volleyball competition = (1 / 5)
As, the sum of their probabilities of winning the competition is still short of 1; so, there must be more teams in the competition.
Assuming that there is no provision for joint winners in the competition; it can be said that, A, B, C, …….. all are mutually exclusive events. Thus, (A Ω Β) = (A Ω C) = (B Ω C) = …….. = Φ (Νull set).
So, P(A Ω Β) = 0.
The answer will be P(A union B) = P(A U B) = P(A) + P(B) - P(A Ω Β) = (1 / 3) + (1 / 9) - 0 = (4 / 9) ≈ 0.4444.