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find the equation of the circle if its radius is 2,tangent to both axes and center in the 4th quadrant.

Sagot :

in the 4th quadrant, x is positive and y is negative

since it's radius is 2 and it's tangent to the x&y axis the coordinates of the center of the circle is (2,-2)

the equation of the circle is: 
[tex](x-2)^2 + (y+2)^2 = 2^2[/tex]