Answered

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(2x+3) (x+4) pakisagot quadratic equation by factoring po iyan

Sagot :

Rodriguezmina94idn
(2x+3)(x+4)=0
2x²+8x+3x+12=0
2x²+11x+12=0

or do you mean this?

(2x+3)(x+4)
[tex] \frac{2x}{2} [/tex] = [tex] \frac{3}{2} [/tex] and x=4

VilesXidn
(2x+3)(x+4)=228
2x²+8x+3x+12=228
2x²+11x=228-12
2(x²+5.5x+121/16)=228-12+2(121/16)
2(x+2.75)²/2=1849/8/2
√(x+2.75)²=±√1849/16
(x+2.75)=±43/4
x+2.75=+43/4    |   x+2.75=-43/4
x=-2.75+43/4     |   x=-2.75-43/4
x=8                   |   x=-13.5

proven by calculator.