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Two airplanes left the same airport traveling in opposite directions. If one airplane averages 400 miles per hour and the other airplane averages 250 miles per hour, in how many hours will the distance between the two planes be 1625 miles?

Sagot :

400mph
250mph
 let x be the distance covered

400x+250x=1625

650x=1625

x=2.5 hours
given:
[tex]v_1=400 mph[/tex]
[tex]v_2=250 mph[/tex]
[tex]d_t=1625 miles[/tex]

req'd:

[tex]t=?[/tex]

formula:

[tex]distance=velocity[/tex]  x  [tex]time[/tex]

since they are traveling in the opposite the total distance is equal to

[tex]d_t=(v_1)(t)+(v_2)(t)[/tex]

since they left at the same time

[tex]t_1=t_2[/tex]

solve for t:

[tex]1625=(400)t+(250)t[/tex]

[tex]1625=650t[/tex]

[tex]t= \frac{1625}{650} [/tex]

[tex]t=2.5 hrs[/tex]