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Sagot :
400mph
250mph
let x be the distance covered
400x+250x=1625
650x=1625
x=2.5 hours
250mph
let x be the distance covered
400x+250x=1625
650x=1625
x=2.5 hours
given:
[tex]v_1=400 mph[/tex]
[tex]v_2=250 mph[/tex]
[tex]d_t=1625 miles[/tex]
req'd:
[tex]t=?[/tex]
formula:
[tex]distance=velocity[/tex] x [tex]time[/tex]
since they are traveling in the opposite the total distance is equal to
[tex]d_t=(v_1)(t)+(v_2)(t)[/tex]
since they left at the same time
[tex]t_1=t_2[/tex]
solve for t:
[tex]1625=(400)t+(250)t[/tex]
[tex]1625=650t[/tex]
[tex]t= \frac{1625}{650} [/tex]
[tex]t=2.5 hrs[/tex]
[tex]v_1=400 mph[/tex]
[tex]v_2=250 mph[/tex]
[tex]d_t=1625 miles[/tex]
req'd:
[tex]t=?[/tex]
formula:
[tex]distance=velocity[/tex] x [tex]time[/tex]
since they are traveling in the opposite the total distance is equal to
[tex]d_t=(v_1)(t)+(v_2)(t)[/tex]
since they left at the same time
[tex]t_1=t_2[/tex]
solve for t:
[tex]1625=(400)t+(250)t[/tex]
[tex]1625=650t[/tex]
[tex]t= \frac{1625}{650} [/tex]
[tex]t=2.5 hrs[/tex]
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