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the length of a swimming pool is 8m longer than its width and the area is 105m squared

Sagot :

VilesXidn
let w be width
let l be length

l = w+8

formula:

A= l x w

105m = (w+8)(w)
105m = w²+8w
105m + 16 = w²+8w+16        (completing the square)
121 = (w+4)²
√121 = ± √(w+4)²                  (square root of both sides)
11 = ± (w+4)
w = 11 - 4
w = 7m

l = w + 8
l = 7 + 8
l = 15m

checking

105 = 15(7)
105 = 105
Raffiekaliidn
My answers is in Quadratic equation.

Let X be the width
X + 8 be the length

A=1 . W= 105m^2
105=x (x+8)

Solve for x
X^2+8x=105
x^2 + 8 -105=0 (Final answer)

 Therefore , the given situation illustrates an Quadratic equation.
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