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what mass of solute is contained in 25.00 ml of a 0.500 M sodium hydroxide solution?​

Sagot :

Solution:

Step 1: Calculate the number of moles of solute.

[tex]\text{molarity} = \frac{\text{moles of solute}}{\text{volume of solution (in L)}}[/tex]

moles of solute = molarity × volume of solution (in L)

moles of solute = 0.500 M × 0.02500 L

moles of solute = 0.0125 mol

Step 2: Calculate the molar mass of solute (NaOH).

molar mass of solute = (22.99 g/mol × 1) + (16.00 g/mol × 1) + (1.008 g/mol × 1)

molar mass of solute = 39.998 g/mol

Step 3: Calculate the mass of solute.

mass of solute = moles of solute × molar mass of solute

mass of solute = 0.0125 mol × 39.998 g/mol

[tex]\boxed{\text{mass of solute = 0.500 g}}[/tex]

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