Solution:
Step 1: Calculate the molar mass of Al₂(SO₄)₃.
molar mass = (26.98 g/mol × 2) + (32.07 g/mol × 3) + (16.00 g/mol × 12)
molar mass = 342.17 g/mol
Step 2: Calculate the percentage composition of Al₂(SO₄)₃.
General Formula:
[tex]\text{percent composition} = \frac{\text{atomic mass of an element × number of atoms in a compound}}{\text{molar mass of compound}} × 100[/tex]
For %Al
[tex]\text{\%Al} = \frac{\text{26.98 g/mol × 2}}{\text{342.17 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%Al = 15.77\%}}[/tex]
For %S
[tex]\text{\%S} = \frac{\text{32.07 g/mol × 3}}{\text{342.17 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%S = 28.12\%}}[/tex]
For %O
[tex]\text{\%O} = \frac{\text{16.00 g/mol × 12}}{\text{342.17 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%O = 56.11\%}}[/tex]
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