A.
1. f(x)=2x
a. f(-3)= -6
b. f(1)= 2
c. f(4) = 8
2. f(x)=2x+
a. f(-3)= -5
b. f(1)= 3
c. f(4) =9
3. f(x)=-3x
a. f(-3)=9
b. f(1) = -3
c. f(4) = -12
B.
f(-3) f(1) f(4)
1. f(x)=2x -6 2 8
2. f(x)=2x+1 -5 3 9
3. f(x) = -3x 9 -3 -12
ORDERED PAIRS
1. (-3,6) (1,2) (4,8)
2. (-3,5) (1,3) (4,9)
3. (-3,9) (1,-3) (4,-12)
TABLE
1. x -3 1 4
f(x) -6 2 8
2. x -3 1 4
f(x) -5 3 9
3. x -3 1 4
f(x) 9 -3 -12
C.
1. f(x)=2x f(-3)= -6 (The value of f at x= -3 is -6)
f(1)= 2 (The value of f at x= 1 is 2)
f(4) = 8 (The value of f at x= 4 is 8)
2. f(x)=2x+1 f(-3)= -5 (The value of f at x= -3 is -5.)
f(1 )= 3 (The value of f at x= 1 is 3.)
f(4) = 9 (The value of f at x= 4 is 9.)
3. f(x) = -3x f(-3)=9 (The value of f at x= -3 is 9.)
f(1) = -3 (The value of f at x= 1 is -3) f(4)=-12 (The value of f at x= 4 is -12.)