Solution:
Step 1: Determine the mass of solute and mass of solution.
In 15.2% by mass, there are 15.2 g of solute in 100.0 g of solution.
Step 2: Calculate the volume of solution.
[tex]\text{volume of solution} = \frac{\text{mass of solution}}{\text{density of solution}}[/tex]
[tex]\text{volume of solution} = \frac{\text{100.0 g}}{\text{1.01 g/mL}}[/tex]
[tex]\text{volume of solution = 99.01 mL = 0.09901 L}[/tex]
Step 3: Calculate the molar mass of solute.
molar mass = (1.008 g/mol × 2) + (16.00 g/mol × 2)
molar mass = 34.016 g/mol
Step 4: Calculate the number of moles of solute.
[tex]\text{moles of solute = 15.2 g H₂O₂} × \frac{\text{1 mol H₂O₂}}{\text{34.016 g H₂O₂}}[/tex]
[tex]\text{moles of solute = 0.44685 mol}[/tex]
Step 5: Calculate the molarity of solution.
[tex]\text{molarity} = \frac{\text{moles of solute}}{\text{volume of solution (L)}}[/tex]
[tex]\text{molarity} = \frac{\text{0.44685 mol}}{\text{0.09901 L}}[/tex]
[tex]\boxed{\text{molarity = 4.51 M}}[/tex]
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