Answer:
i've been busy this past week & couldn't find time to take a peek here at brainly. this is a very late answer but i hope this still helps.
\begin{gathered}vi = 25 \frac{m}{s} \\ vf = 15 \frac{m}{s} \\ a = - 3 \: \frac{m}{ {s}^{2} } \\ t = {?} \\ d = {?} \\ \\ to \: solve \: for \: time(t) \\ use \:kinematics \: equation \: for \: velocity - position : \\ vf = vi + at \\ t = \frac{vf - vi}{a} \\ t = \frac{15 \frac{m}{s} - 25 \frac{m}{s} }{ - 3 \frac{m}{ {s}^{2} } } \\ t = 3.33 \: s \\ \\ to \: solve \: for \: distance \: (d) \\ use \:kinematics \: equation \: for \: position - time : \\ d = (vi)t + \frac{1}{2} a {t}^{2} \\ d = (25 \frac{m}{s} )(3.33s) + \frac{1}{2} ( - 3 \frac{m}{ {s}^{2} } )(3.33s)^{2} \\ d = 83.33m - 16.67m \\ d = 66.67 \: m\end{gathered}
vi=25
s
m
vf=15
s
m
a=−3
s
2
m
t=?
d=?
tosolvefortime(t)
usekinematicsequationforvelocity−position:
vf=vi+at
t=
a
vf−vi
t=
−3
s
2
m
15
s
m
−25
s
m
t=3.33s
tosolvefordistance(d)
usekinematicsequationforposition−time:
d=(vi)t+
2
1
at
2
d=(25
s
m
)(3.33s)+
2
1
(−3
s
2
m
)(3.33s)
2
d=83.33m−16.67m
d=66.67m
