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Sagot :
Answer:A) 3 of 10 is (103)=10.9.83.2.1=10.3.4=120(103)=10.9.83.2.1=10.3.4=120.
B) 3 of 6 is (63)=6.5.43.2.1=5.4=20(63)=6.5.43.2.1=5.4=20.
C) The probability that a committee is of 3 men is 20/120=1/6.
D) Two men and one woman can be chosen in (62)(41)=6.52.141=15.4=60(62)(41)=6.52.141=15.4=60.
E) The probability is 60/120=1/2. //////////////////////////////////////////////////////16
How many different committees can be formed from a group of two women and four men if three people are on the committee and at least one member must be a woman?
210
We are to determine the number of 4 member committees that can be formed from 10 people. This is simple combination problem since order is not important here. So Number of ways = 10C4 = 210.
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