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The maximum load of a horizontal beam that is supported at both ends varies jointly as the width and the square of the height and inversely as the length between the supports. A beam 6 m long, 0.1 m wide, and 0.06 m high supports a load of 360 kg. What is the maximum load supported by a beam 16 m long, 0.2 m wide, and 0.08 m high?

Sagot :

Answer:

24,543/8 or 3,067.875 kg

Step-by-step explanation:

Equation: m = kbd 2/1

909= k (1.2) (2.4)² / (3.6)

909= k (864 / 125) / 3.6

909= k 48 / 25 = k 48/25 ÷ 48 / 25

7,575 / 16=k

M= (7575/16)

M= (6) (1.8)² ÷ 3

M= (73,629/8) ÷3

M= 24,543/8

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