Answered

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How many moles of Mn (OH)2 should react with Al so as to have 10 moles of Al2O3?
Mn(OH)2 + AI → Al(OH)3 +
Mn

Sagot :

Blueiceadaidn

Answer:

15 mol Mn(OH)2

Explanation:

The first step when given a chemical reaction is to balance it. That means there are equal moles of Mn on the reactant side [left] as on the product side [right]. In this case we have manganese hydroxide reacting with aluminum, which is a displacement reaction. So the ff is the balanced reaction:

3 Mn(OH)2 + 2 AI →  2 Al(OH)3 +  3 Mn

Now, get the ratio of how many moles of Mn(OH)2 per moles of Al2O3. The answer is 3:2. That means you need 15 moles of Mn(OH)2

3/2 = x/10

x = 15

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