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Answer:
30 ways
Step-by-step explanation:
Total number of digits is 5.
5!=120
If every digit is distinctive to each other, the number of ways you can arrange it is n!. But if it has x number of a digit, y number of another digit and so on. The number of ways you can write is n!/(x!y!)
So for the question, we have two 1's and two 3's.
That is
[tex] \frac{5!}{2!2!} = \frac{120}{4} = 30[/tex]
Therefore, it can be arranged in 30 ways