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Sagot :
12x³y³z is the answer. You just have to multiply first the numerical coefficient and add the exponent of the same variable
(-6xyz) (-2xy) (xy)
Multiply the 1st, 2nd and 3rd monomial like this:
(-6xyz) (-2xy) (xy)=(-6)(-2) (x)(x)(x) (y)(y)(y)
The result is 12x³y³z, Why the rusult is like this?
Ans: x•x•x = x³ ----- we add the exponent that is why the result is x³
y•y•y = y³ ----- we add the exponent that is why the result is y³
z = z¹ or z
Remember: The exponent of the Variables x, y, and z is one (1) and it can be write like this x¹, y¹ and z¹.
Try to recall the laws of exponent...
Multiply the 1st, 2nd and 3rd monomial like this:
(-6xyz) (-2xy) (xy)=(-6)(-2) (x)(x)(x) (y)(y)(y)
The result is 12x³y³z, Why the rusult is like this?
Ans: x•x•x = x³ ----- we add the exponent that is why the result is x³
y•y•y = y³ ----- we add the exponent that is why the result is y³
z = z¹ or z
Remember: The exponent of the Variables x, y, and z is one (1) and it can be write like this x¹, y¹ and z¹.
Try to recall the laws of exponent...
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