XyntheaLei28idn
Answered

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Mr.s Jacinto asked a carpenter to construct a rectangular bulletin board for her classroom. She told the carpenter that the boards area must be 18 square feet 
QUESTIONS:
1. what are the possible dimension of the bulletin board?
2. how did you determine the possible dimensions of the bulletin board?
3. suppose the length of the board is 7 ft. longer than its width. what equation would represent the given situation
4.how would you describe the equation formulated
5: do you think you can use the equation formulated to find the length and the width of the bulletin board? justify ur answer.
 PLEASEEE! HELP ME :( 
i neeed itt!!!! huhuhubels. 

Sagot :

Joooownaidn
2. Possible dimensions of the bulletin board: 2 ft. by 9 ft. and 3 ft. by 6 ft. 
3. Find two positive numbers whose product equals 18. (Note: Area = length x width) 
4. Let w be the width (in ft.). Then the length is w + 7. Since the area is 18, then w(w+7)=18. (Other variables can be used to represent the length or width of the bulletin board) 
5. Taking the product on the left side of the equation formulated in item 4 yields w2+7w=18 . The highest exponent of the variable involved is 2. 
6. Yes 

Hope it's correct :)))
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