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find the slope intercept equation of a line that passes through points (4,-2) and (1,7)


Sagot :

First, find the slope through the equation (y2-y1)/(x2-x1), which in your case is (7-(-2))/(1-4)=9/-3=-3. So your slope is -3.

Then, substitute any of the points in the equation:
(y-y1)=slope(x-x1), which in your case could be:

1. (y-(-2)=-3(x-4)= y+2=-3x+12= y=-3x+10.

2. (y-7)=-3(x-1)= y-7= -3x+3= y= -3x+10.