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A general equation of a circle is given transform the equation to standard form then give the coordinates of the center and radius X²+y²-2x-8y-47=0​

Sagot :

Answer:

C(1, 4) and r = 8

Step-by-step explanation:

  • Standard Form of a Circle

(x - h)² + (y - k)² = r²

  • Write the Equation

x² + y² - 2x - 8y - 47 = 0

  • Put together terms with common variables and transpose the constant term to the right side.

(x² - 2x) + (y² - 8y) = 47

  • Use completing the square.

(x² - 2x + 1) + (y² - 8y + 16) = 47 + 1 + 16

(x - 1)² + (y - 4)² = 64

  • Find the Center and radius by refering it to the standard form:

C(h, k) = C(1, 4)

r² = 64

√r² = √64

r = 8

Therefore, the Center is at (1, 4) and the radius is 8

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