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how many gram are there in 4g of NH3​

Sagot :

Answer:

Molar mass : Mass of the one mole of the substance is called molar mass

Molar mass is numerically equal in g(gram) to atomic mass in u(unified mass).

Molar mass of the NH3

= 14g + (1×3)g

= 17g/mol

Mass = number of moles × molar mass

4.25 = number of moles × 17

4.25/17 = number of moles

0.25 = number of moles

One mole of any substance contains avogadro number (6.022×10^23) of molecules.

Molecules = number of moles×6.022×10^23

Molecules = 0.25 × 6.022×10^23

Molecules = 1.5055×10^23 “ NH3 ” molecules.

Then,

Atoms = 4 × 1.5055 × 10^23 (because there are 4 atoms i.e 3 atoms of Hydrogen and 1 atom of oxygen )

Atoms = 6.022 × 10^23 “ NH3 atoms ”Molar mass : Mass of the one mole of the substance is called molar mass

Molar mass is numerically equal in g(gram) to atomic mass in u(unified mass).

Molar mass of the NH3

= 14g + (1×3)g

= 17g/mol

Mass = number of moles × molar mass

4.25 = number of moles × 17

4.25/17 = number of moles

0.25 = number of moles

One mole of any substance contains avogadro number (6.022×10^23) of molecules.

Molecules = number of moles×6.022×10^23

Molecules = 0.25 × 6.022×10^23

Molecules = 1.5055×10^23 “ NH3 ” molecules.

Then,

Atoms = 4 × 1.5055 × 10^23 (because there are 4 atoms i.e 3 atoms of Hydrogen and 1 atom of oxygen )

Atoms = 6.022 × 10^23 “ NH3 atoms ”Molar mass : Mass of the one mole of the substance is called molar mass

Molar mass is numerically equal in g(gram) to atomic mass in u(unified mass).

Molar mass of the NH3

= 14g + (1×3)g

= 17g/mol

Mass = number of moles × molar mass

4.25 = number of moles × 17

4.25/17 = number of moles

0.25 = number of moles

One mole of any substance contains avogadro number (6.022×10^23) of molecules.

Molecules = number of moles×6.022×10^23

Molecules = 0.25 × 6.022×10^23

Molecules = 1.5055×10^23 “ NH3 ” molecules.

Then,

Atoms = 4 × 1.5055 × 10^23 (because there are 4 atoms i.e 3 atoms of Hydrogen and 1 atom of oxygen )

Atoms = 6.022 × 10^23 “ NH3 atoms ”

Explanation: