Irishjennelidn
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what is the center and raduis of 4x²+4y²+8x-32y+4=0​

Sagot :

Chaser27idn

what is the center and raduis of 4x²+4y²+8x-32y+4=0

SOLUTION:

[tex]4x {}^{2} + 4y {}^{2} + 8x - 32y + 4 = 0[/tex]

CIRCLE EQUATION

[tex](a,b)²+(y,b)²=r²[/tex]

IS THE CIRCLE EQUATION WITH A RADIUS R, CENTERED AT

[tex](a,b)[/tex]

REWRITE

[tex]4x {}^{2} + 4y {}^{2} + 8x - 32y + 4 = 0[/tex]

IN THE FORM OF STANDARD CIRCLE EQUATION

[tex](x - ( - 1)) {}^{2} + (y - 4) {}^{2} = 4 {}^{2} [/tex]

THEREFOR THE CIRCLE PROPERTIES ARE:

[tex](a,b)=(-1,4),r=4[/tex]

FINAL ANSWER:

[tex]\large\purple{\boxed{Center( -1,4)}}[/tex]

[tex]\large\green{\boxed{Radius = 4}}[/tex]

(√^_^)/