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1. What is the equation of the circle in standard form?
a. (x+1)2 – y+k)2 = r2
c. (x-h )2 + (y-k)2 = r2
b. (x-h)2 = (y-k)2 = r2
2. Which of the following equation of the circle has the center of (0,0)?
d. (y-h)2 + (h-k)2 = r2
a. x2 - y2 = 2r
b. x2 + y2 = 2r
c. x2- y2 = r2
d. x2 + y2 = r2
3. Given center (-5, 3) and a radius of 12 units, what is the equation of the
circle in a standard form?
a. (x-5)2 + (y+3)2= 144
b. (x+5)2 + (y-3)2=144
c. (x-5)2 - (y+3)2= 144
d. (x-5)2 + (y-3)2= 144
4. What is the center and the radius of the circle x2 + y2 -6x -10y + 18= 0?
a. C(-3,5); r=9
b. C(-3,-5); r=4
c. C(3,5); r=-4
d. C(3,5); r=4
5. What is the general equation of the circle given the center at (-2,5) and
a radius of 4 units?
b. x2 + y2 - 4x -10y + 13=0
a. x2 + y2 - 4x + 10y -13=0
d. x2 + y2 + 4x +10y + 13=0
c.x2 + y2 + 4x - 10y +13=0



Patulong po plss ​


Sagot :

Answer:

1.) c. (x-h)² + (y-k)² = r²

2.) d. x² + y² = r²

3.) b. (x+5)² + (y-3)² = 144

4.) d. C (3, 5) ; r = 4

5.) c. x² + y² + 4x - 10y + 13 = 0

Answer:

1. C

2. D

3. B

4. C/D

5. C

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