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Suppose z varies directly as the square of x and inversely as y.If z=2 when x=1/2 and y=1/3,Find z when x=3 and y=4



Sagot :

Answer:

z = 6

Step-by-step explanation:

[tex]z = \frac{ {kx}^{2} }{y} [/tex]

[tex]2 = \frac{ \frac{{1}}{2}^{2}k }{ \frac{1}{3} } [/tex]

2() = ½²k

⅔ = ½² k

⅔ = ¼k

To divide by a fraction, multiply by the reciprocal of that fraction.

[tex] \frac{2 \times 4}{3} = k[/tex]

[tex] \frac{8}{3} = k[/tex]

[tex]z = \frac{ \frac{8}{3}( {3}^{3} ) }{4} [/tex]

[tex]z = \frac{ \frac{8}{3}(9) }{4} [/tex]

[tex]z = \frac{ \frac{72}{3} }{4} [/tex]

[tex] z = \frac{24}{3} [/tex]

z = 6

I hope it's help

Brainliest me