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Sagot :
Given:
[tex]\text{isotopic mass}_{Si-28} = \text{27.9769 amu}[/tex]
[tex]\text{isotopic mass}_{Si-29} = \text{28.9765 amu}[/tex]
[tex]\text{isotopic mass}_{Si-30} = \text{29.9738 amu}[/tex]
[tex]\text{percent abundance}_{Si-28} = 92.23\%[/tex]
[tex]\text{average atomic mass = 28.0854 amu}[/tex]
Unknown:
[tex]\text{percent abundance}_{Si-29}[/tex]
[tex]\text{percent abundance}_{Si-30}[/tex]
Solution:
Step 1: Represent a variable for the unknown percent abundances.
[tex]\text{percent abundance}_{Si-29} = x[/tex]
[tex]\text{percent abundance}_{Si-30} = 100 - (92.23 + x) = 7.77 - x[/tex]
Step 2: Solve for the value of x.
Note: The average atomic mass is multiplied by 100 because the abundances are expressed in percent.
[tex]\text{average atomic mass} = (\text{isotopic mass}_{Si-28})(\text{percent abundance}_{Si-28}) + (\text{isotopic mass}_{Si-29})(\text{percent abundance}_{Si-29}) + (\text{isotopic mass}_{Si-30})(\text{percent abundance}_{Si-30})[/tex]
[tex]28.0854 × 100 = (27.9769)(92.23) + (28.9765)(x) + (29.9738)(7.77 - x)[/tex]
[tex]2808.54 = 2580.3095 + 28.9765x + 232.8964 - 29.9738x[/tex]
[tex]29.9738x - 28.9765x = 2580.3095 + 232.8964 - 2808.54[/tex]
[tex]0.9973x = 4.6659[/tex]
[tex]x = \frac{4.6659}{0.9973}[/tex]
[tex]x = 4.68\%[/tex]
Step 3: Determine the values of unknown percent abundances.
For Si-29
[tex]\text{percent abundance}_{Si-29} = x[/tex]
[tex]\boxed{\text{percent abundance}_{Si-29} = 4.68\%}[/tex]
For Si-30
[tex]\text{percent abundance}_{Si-30} = 7.77 - x[/tex]
[tex]\text{percent abundance}_{Si-30} = 7.77 - 4.68[/tex]
[tex]\boxed{\text{percent abundance}_{Si-30} = 3.09\%}[/tex]
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