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Ten runners join a race. In how many possible ways can they be arranged as first, second and third placers?

Sagot :

Someonejustidn

Answer:

P (10,3) = 720

Step-by-step explanation:

Permutation, order is considered (first, second, third)

P (n,r) = \frac{n!}{(n-r)!}

(n−r)!

n!

P (10, 3) = \frac{10!}{(10-3)!}

(10−3)!

10!

P (10, 3) = \frac{10!}{7!}

7!

10!

P (10, 3) = (10×9×8×7×6×5×4×3×2×1) ÷ (7×6×5×4×3×2×1)

P (10,3) = 10×9×8

P (10,3) = 720

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