Julitocarreon8idn
Answered

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3.(2×+3)(×+5)
4.(2×+3)(×+5)
5.(7×-8y)(3×+5y)
6.(×+5)(×-5)
7.(×+2)(×-2)
8.(3×-1)(3×+1)
9.(×2-10)(×2+10)
10.(2×+y-z)(2×+y+z)
Kadugtong​

Sagot :

Cancer37idn

Answer:

3.2x²+13x+15

4.2x²+13x+15

5.21x²+11xy−40y²

6.x²−25

7.x²−4

8.9x²−1

9.x⁴−100

10.4x²+4xy+y²-z²

Step-by-step explanation:

3.(2x+3)(x+5)

=(2x+3)(x+5)

=(2x)(x)+(2x)(5)+(3)(x)+(3)(5)

=2x2+10x+3x+15

=2x²+13x+15

4.(2x+3)(x+5)

=(2x+3)(x+5)

=(2x)(x)+(2x)(5)+(3)(x)+(3)(5)

=2x2+10x+3x+15

=2x²+13x+15

5.7x−8y)(3x+5y)

=(7x+−8y)(3x+5y)

=(7x)(3x)+(7x)(5y)+(−8y)(3x)+(−8y)(5y)

=21x2+35xy−24xy−40y2

=21x²+11xy-40y²

6. (x+5)(x−5)

=(x+5)(x+−5)

=(x)(x)+(x)(−5)+(5)(x)+(5)(−5)

=x2−5x+5x−25

=x²−25

7.(x+2)(x−2)

=(x+2)(x+−2)

=(x)(x)+(x)(−2)+(2)(x)+(2)(−2)

=x2−2x+2x−4

=x²-4

8.3x−1)(3x+1)

=(3x+−1)(3x+1)

=(3x)(3x)+(3x)(1)+(−1)(3x)+(−1)(1)

=9x2+3x−3x−1

=9x²−1

9.x2−10)(x2+10)

=(x2+−10)(x2+10)

=(x2)(x2)+(x2)(10)+(−10)(x2)+(−10)(10)

=x4+10x2−10x2−100

=x⁴−100

10.2x+y−z)(2x+y+z)

=(2x+y+−z)(2x+y+z)

=(2x)(2x)+(2x)(y)+(2x)(z)+(y)(2x)+(y)(y)+(y)(z)+(−z)(2x)+(−z)(y)+(−z)(z)

=4x2+2xy+2xz+2xy+y2+yz−2xz−yz−z2

=4x²+4xy+y²−z²

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