Answer:
[tex]\sqrt[3]{8} = 8^{\frac{1}{3} }\\\sqrt{40} = 40^{\frac{1}{2} } \\\sqrt[3]{8}^{b} = 8^{\frac{b}{3} } \\\sqrt[3]{8} ^{2} = 8^{\frac{2}{3} } \\\sqrt[4]{16} = 16^{\frac{1}{4} } \\\sqrt[3]{27} =27^{\frac{1}{3} } \\\sqrt{45} =45^{\frac{1}{2} } \\\sqrt[t]{p} ^{s} = p^{\frac{s}{t} } \\\sqrt[3]{8}^{2} = 8^{\frac{2}{3} } \\\sqrt[3]{-343} = (-343)^{\frac{1}{3} }[/tex]
Step-by-step explanation:
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