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What is the molecular formula of a compound with a molar mass of 60.0 grams/mol and an empirical formula of CH4N?​

Sagot :

Solution:

Step 1: Represent a molecular formula.

[tex]\text{molecular formula} = (\text{C}\text{H}_{4}\text{N})_{n}[/tex]

Step 2: Calculate the empirical mass.

empirical mass = (12.01 g/mol × 1) + (1.008 g/mol × 4) + (14.01 g/mol × 1)

empirical mass = 30.05 g/mol

Step 3: Divide the molecular mass by the empirical mass.

[tex]n = \frac{\text{molecular mass}}{\text{empirical mass}}[/tex]

[tex]n = \frac{\text{60.0 g/mol}}{\text{30.05 g/mol}}[/tex]

[tex]n = 2[/tex]

Step 4: Multiply the subscripts by the value of n to obtain the molecular formula.

[tex]\text{molecular formula} = (\text{C}\text{H}_{4}\text{N})_{2}[/tex]

[tex]\boxed{\text{molecular formula} = \text{C}_{2}\text{H}_{8}\text{N}_{2}}[/tex]

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