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Activity 2: Know My Percentage!
A Solve the percentage composition of an underlined atom being asked in a compound
1. Na S
²
2. Fe(OH)
²
3. CaSO

4. Al(HCO )
³ ³
5. Zn(CIO )
² ²​


Activity 2 Know My PercentageA Solve The Percentage Composition Of An Underlined Atom Being Asked In A Compound1 Na S2 FeOH 3 CaSO4 AlHCO 5 ZnCIO class=

Sagot :

Solution (1)

Step 1: Calculate the molar mass of Na₂S.

molar mass = (22.99 g/mol × 2) + (32.07 g/mol × 1)

molar mass = 78.05 g/mol

Step 2: Calculate the percentage composition of Na in Na₂S.

[tex]\text{mass percent of Na} = \frac{\text{22.99 g/mol × 2}}{\text{78.05 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Na = 58.91\%}}[/tex]

Solution (2)

Step 1: Calculate the molar mass of Fe(OH)₂.

molar mass = (55.85 g/mol × 1) + (16.00 g/mol × 2) + (1.008 g/mol × 2)

molar mass = 89.87 g/mol

Step 2: Calculate the percentage composition of O in Fe(OH)₂.

[tex]\text{mass percent of O} = \frac{\text{16.00 g/mol × 2}}{\text{89.87 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of O = 35.61\%}}[/tex]

Solution (3)

Step 1: Calculate the molar mass of CaSO₄.

molar mass = (40.08 g/mol × 1) + (32.07 g/mol × 1) + (16.00 g/mol × 4)

molar mass = 136.15 g/mol

Step 2: Calculate the percentage composition of Ca in CaSO₄.

[tex]\text{mass percent of Ca} = \frac{\text{40.08 g/mol × 1}}{\text{136.15 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of Ca = 29.44\%}}[/tex]

Solution (4)

Step 1: Calculate the molar mass of Al(HCO₃)₃.

molar mass = (26.98 g/mol × 1) + (1.008 g/mol × 3) + (12.01 g/mol × 3) + (16.00 g/mol × 9)

molar mass = 210.03 g/mol

Step 2: Calculate the percentage composition of H in Al(HCO₃)₃.

[tex]\text{mass percent of H} = \frac{\text{1.008 g/mol × 3}}{\text{210.03 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of H = 1.44\%}}[/tex]

Solution (5)

Step 1: Calculate the molar mass of Zn(ClO₂)₂.

molar mass = (65.39 g/mol × 1) + (35.45 g/mol × 2) + (16.00 g/mol × 4)

molar mass = 200.29 g/mol

Step 2: Calculate the percentage composition of O in Zn(ClO₂)₂.

[tex]\text{mass percent of O} = \frac{\text{16.00 g/mol × 4}}{\text{200.29 g/mol}} × 100[/tex]

[tex]\boxed{\text{mass percent of O = 31.95\%}}[/tex]

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