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(y³-y+4)(3y²-1) FOIL method
(2d³-2d²+4)(5d²-2d+1)
(5x³-x)(2x⁴+x²+2x-2)
(3b²+b-2)(2b³-2b²-7)
(y⁴+y³)³


Sagot :

In the given problem, apply your knowledge in algebraic expression and basic mathematics specially in solving polynomials.

Multiplication of Polynomials

(y³ - y + 4)(3y² - 1)

3y⁵ - y³ - 3y³ - y + 12y² - 4

= 3y⁵ - 4y³ + 11y² - 4

(2d³ - 2d² + 4)(5d² - 2d + 1)

10d⁵ - 4d⁴ + 2d³ - 10d⁴ + 4d³ - 2d² + 10d² - 8d + 4

= 10d⁵ -14d⁴ + 6d³ + 8d² - 8d + 4

(5x³ - x)(2x⁴ + x² + 2x - 2)

10x⁷ + 5x⁵ + 10x⁴ - 10x³ - 2x⁵ - x³ - 2x² + 2x

= 10x⁷ + 3x⁵ + 10x⁴ - 11x³ - 2x² + 2x

(3b² + b - 2)(2b³ - 2b² - 7)

6b⁵ - 6b⁴ - 21b² + 2b⁴ - 2b³ - 7b - 4b³ - 4b² + 14

= 6b⁵ - 4b⁴ - 6b³ - 25b² - 7b + 14

(y⁴ + y³)³

(y⁴ + y³)³ = (y⁴ + y³)(y⁴ + y³)(y⁴ + y³)

(y⁴ + y³)(y⁴ + y³) = y⁸ + 2y³y⁴ + y⁶

(y⁴ + y³)(y⁸ + 2y³y⁴ + y⁶)

y¹² + 2y³y⁸ + y¹⁰ + y¹¹ + 2y⁶y⁴ + y⁹

= y¹² + y¹¹ + y¹⁰ + 2y³y⁸ + 2y⁶y⁴ + y⁹

Learn more about foil method here at

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