Makakuha ng mabilis at malinaw na mga sagot sa IDNStudy.com. Magtanong ng anumang bagay at makatanggap ng detalyadong sagot mula sa aming komunidad ng mga eksperto.

At a certain time a particle had a speed of 18 m/s in the positive x direction, and 2.4 s

later its speed was 30 m/s in the opposite direction. What is the average acceleration of the

particle during this 2.4 s interval?


Sagot :

Answer:

5m/s²

Step-by-step explanation:

(30m/s - 18m/s)/2.4 s

=(12m/s)/2.4s

=5m/s²

pa-brainliest nalang po thx