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1. Sucrose or known as the table sugar has a molar mass of 342.1 g/mol. What is the percentage composition of each element in this compound? (Atomic masses: C=12.01 g; H=1.001g; O=16.00g from the periodic table)​

1 Sucrose Or Known As The Table Sugar Has A Molar Mass Of 3421 Gmol What Is The Percentage Composition Of Each Element In This Compound Atomic Masses C1201 G H1 class=

Sagot :

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Answer:

C=42.1%

H=6.4%

O=51.4%

Step-by-step explanation:

Step 1.

[tex]c = \frac{12.01(12)}{342.1g \: per \: mol} \times 100[/tex]

[tex]h = \frac{1.001(22)}{342.1g \: per \: mol} \times 100[/tex]

[tex]o = \frac{16(11)}{342.1g \: per \: mol} \times 100[/tex]

Step 2

C=12.01(12)÷342.1g/mol x 100

12.01 x 12=144.12÷342.1g/mol=

0.42128032739 x 100=42.128032739 (round off to the nearest tenth)=42.1%

H=1.001(22)÷342.1g/mol x 100

1.001 x 22=22.022÷342.1g/mol

=0.06437299035 x 100=6.437299035 (round off to the nearest tenth)=6.4%

O=16(11)÷342.1g/mol x 100

16 x 11=176÷342.1g/mol=

0.51446945338 x 100=51.446945338 (round off to the nearest tenth)=51.4%

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