SilentAJidn
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1. Kian is twice as old as Xhendric. The sum of their age is 36. How old are they?
2. The bigger number is three more than the smaller number. If their sum is 81. What are the numbers?
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Sagot :

Callmekillyidn

Answer:

1. Kian= 24 yrs old and Xhendric= 12 yrs old

2. the numbers are 42 and 39

Step-by-step explanation:

1. Let x be the age of Xhendric ( since he is the youngest).

Xhendric= x                       Kian = 2x (because he is twice the age of Xhendric)

Kian's Age + Xhendric's Age = 36

2x + x = 36

3x = 36

3x/3  = 36/3 (to get the value of x we must divide both side by 3)

x= 12

Xhendric = (x)= 12 yrs old          Kian = 2(12) = 24 yrs old

2.  Let x be the smaller number

Bigger number: x+3        Smaller number: x

x + (x+3) = 81

2x+3 = 81

to get the value of x we must first eliminate all numbers beside x, which is +3. to eliminate it we must transpose or move it to the other side of the equation, beside 81.

2x = 81-3

( when we transpose a number their sign changes if its positive it becomes negative and if its negative it becomes positive.)

2x = 78 ( To get the value of x, we must divide both sides by 2)

2x/2 =78/2

x= 39

Bigger number : x + 3 = (39)+ 3 = 42

Smaller number: x = 39

42+39 = 81

                   

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