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Find the areas of squares whose sides measure:
a) 10 m c) 42 cm
b. .62 dm d) 6 080 cm


Sagot :

[tex]Area=s^2 \\ a.(10m)^2=100m^2 \\ b. (0.62dm)^2=0.3844dm^2 \\ c.(42cm)^2=1764cm^2 \\ d.(6080cm)^2=36,966,400cm^2[/tex]
The formula for the area of the square is:
A=s²

Substitute
1)side=10 m
A=(10 m)²
A=100 m²

2)side=0.62 dm
A=(0.62 dm)²
A=0.38 dm²

3)side=42 cm
A=(42 cm)²
A=1,764 cm²

4.side=6,080 cm
A=(6,080 cm)²
A=36,966,400 cm²

Hope this helps =)