Moorechien19idn
Answered

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Mr. Agpalo paid Php 260 for 4 adult’s tickets and 6 children’s tickets. Suppose the total cost of an adult's ticket and a children’s ticket is Php 55. How much does an adult's ticket cost?

Sagot :

Mlcparra16idn
We let the price of an adult's ticket be A and C for children.

We have two equations:
4A + 6C = 260...[1]
A + C =55 ... [2]

We need to remove C in order to know the value of A so:
6[2] - [1]
 6A + 6C = 330
-4A - 6C = -260
     2A   = 70
       A   = 35

Therefore the cost of an adult's ticket is P35


Jers15idn
Lets represent:
x=cost of adult ticket
y=cost of children ticket

The equation are
4x+6y=260
x+y=55

For the second equation, find the value of x
x+y=55
x=55-y
After finding it, substitute it to the first equation
4(55-y)+6y=260
220-4y+6y=260
Add like terms
220+2y=260
Subtract both sides by 220
2y=40
y=20

Substitute the value of y to any equation
x+y=55
x+20=55
Subtract both sides by 20
x=35

Hope this helps =)
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