We need to work backwards in this problem. We need to do the opposite of whatever the operation is and start with the result. At the last part we are given 1 fish that he gave to George then he gave half a fish and half of the remaining to Bob. Since in the problem "giving" is subtracting we now add and instead of dividing by 2 we multiply so the expression will be:
[tex]2(1+ \frac{1}{2} )= 3[/tex]
So we now have 3 fish. Going back he gave half a fish and half of the remaining to Angel so we use the same logic as we did awhile ago.
[tex]2(3+ \frac{1}{2} )=7[/tex]
Therefore Miguel had 7 fish at the start