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"Mrs. Jacinto asked a carpenter to construct a rectangular bulletin board for her classroom. She told the carpenter that the board's area must be 18 sq. ft." Q: What are the possible dimensions of the bulletin board? 2.Give at least 2 pairs of possible dimensions.Explain how did you determine the possible dimensions of the bulletin board. 3.suppose the length of the board is 7ft longer than its width . what equation would represent tge given situation? 4.how would you describe the equation formulated?. please.. .help me!!. :'(

Sagot :

VilesXidn
Given:
A = 18 ft²

formula for the area of a rectangle is:
length x width 

lets use:

A = l x w 

solution by trial and error.

so the area must be 18 ft²

let l be any real number greater than 0 but less than or equal to 18

0 < l ≤ 18

assume any value of l greater than 0 but less than or equal to 18

like l = 3ft

 A = 3 x w
18 = 3 x w
w = 6ft

or l = 4ft

18 = 4 x w
w = 4.5 ft

check

A = l x w

for l = 3 
A = 3 x 6
A = 18 ft²

for l = 4 
A = 4 x 4.5
A = 18 ft²

3.)

let w = l+7
A = l x w
by substitution
18 = l x ( l + 7)
18 = 2l² + 7l
l = 2 ft

w = l + 7
w = 2 + 7
w = 9 ft

check

18 = 9 x 2
18 = 18

4.
18 = 2l² + 7l

2l² + 7l -18 = 0 is a quadratic equation

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