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Sagot :
Given:
Salary for the year = P68, 200
Find:
Salary for a month
Solution:
1 year = P68, 200
1 year = 12 months
1 year = 12 months = P68, 200
12 months = P68, 200
[tex] \frac{12-months = P68, 200}{12} [/tex]
1 month = P5, 683. 33 (needs to be rounded up)
Final Answer:
P5, 684 (rounded up)
Salary for the year = P68, 200
Find:
Salary for a month
Solution:
1 year = P68, 200
1 year = 12 months
1 year = 12 months = P68, 200
12 months = P68, 200
[tex] \frac{12-months = P68, 200}{12} [/tex]
1 month = P5, 683. 33 (needs to be rounded up)
Final Answer:
P5, 684 (rounded up)
[tex]\bold{Given:} \\ .\ \bold{_{Salary}}\ \ \ \ \ \ \ \ \ \ \ \ \bold{_{Time}} \\ .\ \ \downarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow \\ ^{\bold{Php}\ 68,200}\ \ \ \ \ \ \ \ \ \ \bold{^{year}} \\ .\ \ \ \ \ \ \ \ \ \ _{\bold{(Problem)}} \\ \bold{_{What\ is\ the\ monthly\ salary?}} [/tex]
[tex]^{------------------------------------------------}[/tex]
[tex]\bold{Solution:}[/tex]
[tex]^{------------------------------------------------}[/tex]
[tex]\\ \\ _{\bold{Equation:}} \\ \\ \bold{Php}\ 68,200}={1\ \bold{year}[/tex]
[tex]1\ \bold{year}=12\ \bold{months} \\ \\ 1\ \bold{year}=12\ \bold{months}=\bold{Php}\ 60,200[/tex]
[tex]^{------------------------------------------------}[/tex]
[tex]\bold{Final\ Solution:} \\ \\ \frac{\bold{Php}\ 60,200}{12\ \bold{months}}=\bold{Php}\ 5,683.33 \\ \\ \bold{Php}\ 5,683.33\ _{\bold{(round\ up)}}=\ \boxed{\boxed{\bold{Php}\ 5,684}} \\ \\ \bold{Conclusion}:\\ \\ Therefore,\ Teamin's\ father\ earns\ \underline{\bold{Php}\ 5,684}}\ a\ month.[/tex]
[tex]^{------------------------------------------------}[/tex]
[tex]Hope\ it\ Helps:) \\ Domini[/tex]
[tex]^{------------------------------------------------}[/tex]
[tex]\bold{Solution:}[/tex]
[tex]^{------------------------------------------------}[/tex]
[tex]\\ \\ _{\bold{Equation:}} \\ \\ \bold{Php}\ 68,200}={1\ \bold{year}[/tex]
[tex]1\ \bold{year}=12\ \bold{months} \\ \\ 1\ \bold{year}=12\ \bold{months}=\bold{Php}\ 60,200[/tex]
[tex]^{------------------------------------------------}[/tex]
[tex]\bold{Final\ Solution:} \\ \\ \frac{\bold{Php}\ 60,200}{12\ \bold{months}}=\bold{Php}\ 5,683.33 \\ \\ \bold{Php}\ 5,683.33\ _{\bold{(round\ up)}}=\ \boxed{\boxed{\bold{Php}\ 5,684}} \\ \\ \bold{Conclusion}:\\ \\ Therefore,\ Teamin's\ father\ earns\ \underline{\bold{Php}\ 5,684}}\ a\ month.[/tex]
[tex]^{------------------------------------------------}[/tex]
[tex]Hope\ it\ Helps:) \\ Domini[/tex]
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