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Taemin's father earns Php68,200 a year. what is his monthly salary?

Sagot :

Jeremiaidn
Given:
                Salary for the year = P68, 200

Find:
          Salary for a month

Solution:
               1 year = P68, 200  
               1 year = 12 months
               1 year = 12 months = P68, 200
                12 months = P68, 200
               
                 [tex] \frac{12-months = P68, 200}{12} [/tex]
  
                 1 month = P5, 683. 33 (needs to be rounded up)

Final Answer:
                         P5, 684 (rounded up)


Dominiidn
[tex]\bold{Given:} \\ .\ \bold{_{Salary}}\ \ \ \ \ \ \ \ \ \ \ \ \bold{_{Time}} \\ .\ \ \downarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow \\ ^{\bold{Php}\ 68,200}\ \ \ \ \ \ \ \ \ \ \bold{^{year}} \\ .\ \ \ \ \ \ \ \ \ \ _{\bold{(Problem)}} \\ \bold{_{What\ is\ the\ monthly\ salary?}} [/tex]
[tex]^{------------------------------------------------}[/tex]

[tex]\bold{Solution:}[/tex] 
[tex]^{------------------------------------------------}[/tex]
[tex]\\ \\ _{\bold{Equation:}} \\ \\ \bold{Php}\ 68,200}={1\ \bold{year}[/tex]

[tex]1\ \bold{year}=12\ \bold{months} \\ \\ 1\ \bold{year}=12\ \bold{months}=\bold{Php}\ 60,200[/tex] 
[tex]^{------------------------------------------------}[/tex]
[tex]\bold{Final\ Solution:} \\ \\ \frac{\bold{Php}\ 60,200}{12\ \bold{months}}=\bold{Php}\ 5,683.33 \\ \\ \bold{Php}\ 5,683.33\ _{\bold{(round\ up)}}=\ \boxed{\boxed{\bold{Php}\ 5,684}} \\ \\ \bold{Conclusion}:\\ \\ Therefore,\ Teamin's\ father\ earns\ \underline{\bold{Php}\ 5,684}}\ a\ month.[/tex]

[tex]^{------------------------------------------------}[/tex]

[tex]Hope\ it\ Helps:) \\ Domini[/tex]
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