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Solve the system of linear of equation for x and y using elimination method and check by using substitution method.
3x-y =5
2x+y =10

Sagot :

Dominiidn
[tex]Here's\ the\ solution; \\ \\ Elimination\ method; \\ \\ 3x-\not{y}=5\to equation\ 1 \\ 2x+\not{y}=10\to equation\ 2 \\ ^{--------} \\ \frac{\not5x}{\not5}=\frac{15}{5} \\ \\ \boxed{x=3} \\ \\ Solving\ for\ y: \\ by\ using\ equation\ 1 \\ \\ 3x-y=5 \\ \\ 3(3)-y=5\ \ \ \ \ \ \ \ |\ Substitute\ x\to3 \\ \\ 9-y=5 \\ \\ -y=5-9 \\ \\ \frac{-y}{-1}=\frac{-4}{-1} \\ \\ \boxed{y=4} [/tex]

[tex]You\ can\ use\ equation\ 2\ if\ you\ want\ too\ in\ finding \\ the\ value\ of\ y. \\ Well,\ here's\ the\ solution\ by\ using\ equation\ 2. \\ \\ 2x+y=10 \\ \\ 2(3)+y=10\ \ \ \ \ \ \ \ \ |\ Substitute\ x\to3 \\ \\ 6+y=10 \\ \\ y=10-6 \\ \\ \boxed{y=4} \\ \\ \\ Conclusion: \\ Therefore,\ the\ value\ of\ x\ and\ y\ is\ 3\ and\ 4\ respectively. \\ \\ Hope\ it\ Helps\ :) \\ Domini[/tex]
Jers15idn
3x-y=5
2x+y=10

Add the 2 equations:
5x=15
Divide both sides by 5
x=3

Now, substitute the value of x to any equation
2x+y=10
2(3)+y=10
6+y=10
Subtract both sides by 6
y=4

To check(substitute the values):
2x+y=10
2(3)+4=10
6+4=10
10=10

Another equation:
3x-y=5
3(3)-4=5
9-4=5
5=5

Therefore the values are correct... Hope this helps =)
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