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A cricle has its center of (-1,7) and one of its diamter is at (1,2). Find the other end of this Diameter.


Sagot :

Given:
C(-1,7)
P(1,2)

given that P is the other end of diameter and C is the center we can say that C is the mid point of the diameter. to find the other end we use the mid point of a line segment formula:

[tex] x_{m} = \frac{ x_{1}+ x_{2} }{2} [/tex]

                                  and

[tex] y_{m} = \frac{ y_{1}+ y_{2} }{2} [/tex]

Solution:

[tex] -1 = \frac{1+ x_{2} }{2} [/tex]

[tex] x_{2} = -3[/tex]

[tex] 7 = \frac{2+ y_{2} }{2} [/tex]

[tex] y_{2} = 12[/tex]

therefor, the other end of diameter or [tex] P_{2} [/tex]

[tex] P_{2}(-3,12) [/tex]