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please help me...
find three consecutive odd integers such that 2 times the sum of the first two is 1 less than 3 times the third. thanks!


Sagot :

3 consecutive odd numbers are unknown so we can state them as:
x, x+2, x+4.

2(x+x+2)=3(x+4)-1
Distribute first
2x+2x+4=3x+12-1
Add like terms
4x+4=3x+11
Subtract both sides by 3x and 4
x=7

Now the odd numbers are 7, 9, 11. Hope this helps =)