Ramonedusty297idn
Answered

Makakuha ng mga sagot sa iyong mga tanong mula sa komunidad ng IDNStudy.com. Hanapin ang mga solusyong kailangan mo nang mabilis at tiyak sa tulong ng aming mga bihasang miyembro.

What is the width of a lot with a perimeter of 58 meters and a length of 17.5 meters?

Sagot :

Palsme9971idn
the question stated that the lot figure is a rectangle because of the given of length and width.

P=2(l+w)--- where
                P= perimeter --l= length -- w= width
58m= 2(17.5+w)
58= 35+2w
w= 11.5 meters
Bellalesseidn
What is the width of a lot with a perimeter of 58 meters and a length of 17.5 meters?

Perimeter = 2(length)+2(width)

Given: Length = 17.5 meters
           Perimeter = 58 meters

Required: Width

Equation: Perimeter = 2(length)+2(width)

Solution: 58 meters = 2(17.5 meters) + 2n
               58 meters = 35 meters + 2n
               -2n = 35 meters - 58 meters
               -2n = -23
               [tex] \frac{-2n}{-2} = \frac{-23}{-2} [/tex]
              n = 11.5

Answer: The width of the lot with a perimeter of 58 meters and a length of 17.5 meters is 11.5 meters.

Check: Perimeter = 2(length)+2(width)
            58 meters = 2(17.5 meters) + 2(11.5 meters)
            58 meters = 35 + 23 meters
            58 meters = 58 meters