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Sagot :
3x-y=3
2x+y=2
To solve this, use one method which is elimination. To eliminate, add or subtract(I prefer add) the 2 equations
5x=5
Divide both sides by 5
x=1
After you find the value of a number, substitute.
2x+y=2
2+y=2
y=0
Now, to graph this, we can use methods like intercept form
3x-y=3
x=0; y=0
y=-3; x=1
Coordinates of first equation:(0,-3)(1,0)
These are coordinates, just make a line crossing these points
The second equation
2x+y=2
x=0; y=0
y=2; x=1
coordinates of 2nd equation: (0,2)(1,0)
Just connect a line between these 2 points.
Hope this helps =)
2x+y=2
To solve this, use one method which is elimination. To eliminate, add or subtract(I prefer add) the 2 equations
5x=5
Divide both sides by 5
x=1
After you find the value of a number, substitute.
2x+y=2
2+y=2
y=0
Now, to graph this, we can use methods like intercept form
3x-y=3
x=0; y=0
y=-3; x=1
Coordinates of first equation:(0,-3)(1,0)
These are coordinates, just make a line crossing these points
The second equation
2x+y=2
x=0; y=0
y=2; x=1
coordinates of 2nd equation: (0,2)(1,0)
Just connect a line between these 2 points.
Hope this helps =)
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