Bubbleidn
Answered

Sumali sa IDNStudy.com at makakuha ng mga sagot sa iyong mga tanong. Hanapin ang mga solusyong kailangan mo nang mabilis at madali sa tulong ng aming mga eksperto.

analytic geometry:perpendicular to y=7x+1 and passing at a diistance square root of 2 from (4,-2)

Sagot :

perpendicular to line y=7x+1 (rearranging it) -> 7x-y=1

for a line to be perpendicular just interchange the constant of the 2 variables and change the sign of y

x+7y+P=0

now we have to solve for P using the formula of distance from a line to a point

d=| (Ax_{1} + By_{1} + P)/(sqrt(A^2 + B^2)) | (absolute value)

where:
d=sqrt2
x_{1}=4
y_{1}=-2
A=1
B=7

sqrt2=| { (1*4) + (7*-2) + P }/(sqrt50) |

solving for P gives you P=20 so the line is x+7y+20=0