IDNStudy.com, kung saan nagtatagpo ang mga eksperto para sagutin ang iyong mga tanong. Makakuha ng impormasyon mula sa aming mga eksperto, na nagbibigay ng maaasahang sagot sa lahat ng iyong mga tanong.
Sagot :
Evaluate (5x² + 3xy) over xy² using the given values of x and y below:
1.) x = -2; y = -2
[tex] \frac{5x^{2}+ 3xy}{xy^{2}} [/tex]
[tex] \frac{5(-2)^{2} + 3(-2)(-2)}{(-2)(-2)^{2}} [/tex]
[tex] \frac{5(4)+3(4)}{(-2)(4)} [/tex]
[tex] \frac{20+12}{-8} [/tex]
[tex] \frac{32}{-8} [/tex]
-4
2.) x = 1; y = -1
[tex] \frac{(5 x^{2} + 3xy)}{x y^{2} } [/tex]
[tex] \frac{5(1)^{2} +3(1)(-1)}{(1)(-1)^{2} } [/tex]
[tex]\frac{5(1) + 3(-1)}{(1)(1)} [/tex]
[tex]\frac{5 - 3}{1} [/tex]
[tex] \frac{2}{1} [/tex]
2
3.) x = -2; y = -1
[tex] \frac{(5x^{2} +3xy)}{xy^{2}} [/tex]
[tex] \frac{5(-2)^{2} +3(-2)(-1)}{(-2)(-1)^{2}}[/tex]
[tex] \frac{5(4)+3(2)}{(-2)(1)}[/tex]
[tex] \frac{20 + 6}{-2} \frac{26}{-2} -13[/tex]
4.) x = -1; y = -2
[tex] \frac{5x^{2} + 3xy}{xy^{2} } [/tex]
[tex] \frac{5(-1)^{2} + 3(-1)(-2)}{(-2)^{2}} [/tex]
[tex] \frac{5(1) + 3(2)}{(-1)(4)} [/tex]
[tex] \frac{5 + 6}{-4} [/tex]
[tex] \frac{11}{-4} [/tex]
-2.75
5.) x = 8; y = 7
[tex] \frac{5x^{2} + 3xy}{xy^{2} } [/tex]
[tex] \frac{5(8)^{2} + (3)(8)(7)}{8(7)^{2}} [/tex]
[tex] \frac{5(64) + 24(7)}{8(49)} [/tex]
[tex] \frac{320 + 168}{392} [/tex]
[tex] \frac{488}{392} [/tex]
[tex] 1\frac{96}{392} or 1 \frac{12}{49} [/tex]
1.) x = -2; y = -2
[tex] \frac{5x^{2}+ 3xy}{xy^{2}} [/tex]
[tex] \frac{5(-2)^{2} + 3(-2)(-2)}{(-2)(-2)^{2}} [/tex]
[tex] \frac{5(4)+3(4)}{(-2)(4)} [/tex]
[tex] \frac{20+12}{-8} [/tex]
[tex] \frac{32}{-8} [/tex]
-4
2.) x = 1; y = -1
[tex] \frac{(5 x^{2} + 3xy)}{x y^{2} } [/tex]
[tex] \frac{5(1)^{2} +3(1)(-1)}{(1)(-1)^{2} } [/tex]
[tex]\frac{5(1) + 3(-1)}{(1)(1)} [/tex]
[tex]\frac{5 - 3}{1} [/tex]
[tex] \frac{2}{1} [/tex]
2
3.) x = -2; y = -1
[tex] \frac{(5x^{2} +3xy)}{xy^{2}} [/tex]
[tex] \frac{5(-2)^{2} +3(-2)(-1)}{(-2)(-1)^{2}}[/tex]
[tex] \frac{5(4)+3(2)}{(-2)(1)}[/tex]
[tex] \frac{20 + 6}{-2} \frac{26}{-2} -13[/tex]
4.) x = -1; y = -2
[tex] \frac{5x^{2} + 3xy}{xy^{2} } [/tex]
[tex] \frac{5(-1)^{2} + 3(-1)(-2)}{(-2)^{2}} [/tex]
[tex] \frac{5(1) + 3(2)}{(-1)(4)} [/tex]
[tex] \frac{5 + 6}{-4} [/tex]
[tex] \frac{11}{-4} [/tex]
-2.75
5.) x = 8; y = 7
[tex] \frac{5x^{2} + 3xy}{xy^{2} } [/tex]
[tex] \frac{5(8)^{2} + (3)(8)(7)}{8(7)^{2}} [/tex]
[tex] \frac{5(64) + 24(7)}{8(49)} [/tex]
[tex] \frac{320 + 168}{392} [/tex]
[tex] \frac{488}{392} [/tex]
[tex] 1\frac{96}{392} or 1 \frac{12}{49} [/tex]
Evaluate means like find the value given a certain amount. Ex:
1.x=-2; y=-2
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
Sustitute
[tex]\frac{5(-2)^2+3(-2)(-2)}{-2(-2)^2}[/tex]
[tex]\frac{20+12}{-8}[/tex]
Add like terms
[tex]\frac{32}{-8}[/tex]
Divide:
=-4
2.x=1; y=-1
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
Substitute
[tex]\frac{5(1)^2+3(1)(-1)}{1(-1)^2}[/tex]
[tex]\frac{5-3}{1}[/tex]
Add like terms
=2
3.x=-2; y=-1
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
Substitute
[tex]\frac{5(-2)^2+3(-2)(-1)}{-2(-1)^2}[/tex]
[tex]\frac{20+6}{-2}[/tex]
Add like terms
[tex]\frac{26}{-2}[/tex]
Divide
=-13
4.x=-1; y=-2
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
[tex]\frac{5(-1)^2+3(-1)(-2)}{-1(-2)^2}[/tex]
[tex]\frac{5+6}{-4}[/tex]
Add like terms
[tex]\frac{11}{-4}[/tex]
Divide
=-11/4 or -2.75
5.x=8; y=7
Substitute:
[tex]\frac{5(8)^2+3(8)(7)}{7(8)^2}[/tex]
[tex]\frac{320+168}{448}[/tex]
Add like terms
[tex]\frac{488}{488}{/tex]
Divide
=1
Hope this helps =)
1.x=-2; y=-2
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
Sustitute
[tex]\frac{5(-2)^2+3(-2)(-2)}{-2(-2)^2}[/tex]
[tex]\frac{20+12}{-8}[/tex]
Add like terms
[tex]\frac{32}{-8}[/tex]
Divide:
=-4
2.x=1; y=-1
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
Substitute
[tex]\frac{5(1)^2+3(1)(-1)}{1(-1)^2}[/tex]
[tex]\frac{5-3}{1}[/tex]
Add like terms
=2
3.x=-2; y=-1
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
Substitute
[tex]\frac{5(-2)^2+3(-2)(-1)}{-2(-1)^2}[/tex]
[tex]\frac{20+6}{-2}[/tex]
Add like terms
[tex]\frac{26}{-2}[/tex]
Divide
=-13
4.x=-1; y=-2
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
[tex]\frac{5(-1)^2+3(-1)(-2)}{-1(-2)^2}[/tex]
[tex]\frac{5+6}{-4}[/tex]
Add like terms
[tex]\frac{11}{-4}[/tex]
Divide
=-11/4 or -2.75
5.x=8; y=7
Substitute:
[tex]\frac{5(8)^2+3(8)(7)}{7(8)^2}[/tex]
[tex]\frac{320+168}{448}[/tex]
Add like terms
[tex]\frac{488}{488}{/tex]
Divide
=1
Hope this helps =)
Salamat sa iyong kontribusyon. Huwag kalimutang bumalik upang magtanong at matuto ng mga bagong bagay. Ang iyong kaalaman ay mahalaga sa ating komunidad. Bawat tanong ay may sagot sa IDNStudy.com. Salamat at sa muling pagkikita para sa mas maraming solusyon.