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Instruction: Evaluate (5x² + 3xy) over xy² using the given values of x and y below

1.) x= -2; y= -2
2.) x= 1; y= -1
3.) x= -2; y= -1
4.) x= -1; y= -2
5.) x= 8; y= 7


Sagot :

Evaluate (5x² + 3xy) over xy² using the given values of x and y below:

1.) x = -2; y = -2
[tex] \frac{5x^{2}+ 3xy}{xy^{2}} [/tex]
[tex] \frac{5(-2)^{2} + 3(-2)(-2)}{(-2)(-2)^{2}} [/tex]
[tex] \frac{5(4)+3(4)}{(-2)(4)} [/tex]
[tex] \frac{20+12}{-8} [/tex]
[tex] \frac{32}{-8} [/tex]
-4

2.) x = 1; y = -1
[tex] \frac{(5 x^{2} + 3xy)}{x y^{2} } [/tex]
[tex] \frac{5(1)^{2} +3(1)(-1)}{(1)(-1)^{2} } [/tex]
[tex]\frac{5(1) + 3(-1)}{(1)(1)} [/tex]
[tex]\frac{5 - 3}{1} [/tex]
[tex] \frac{2}{1} [/tex]
2

3.) x = -2; y = -1
[tex] \frac{(5x^{2} +3xy)}{xy^{2}} [/tex]
[tex] \frac{5(-2)^{2} +3(-2)(-1)}{(-2)(-1)^{2}}[/tex]
[tex] \frac{5(4)+3(2)}{(-2)(1)}[/tex]
[tex] \frac{20 + 6}{-2} \frac{26}{-2} -13[/tex]

4.) x = -1; y = -2
[tex] \frac{5x^{2} + 3xy}{xy^{2} } [/tex]
[tex] \frac{5(-1)^{2} + 3(-1)(-2)}{(-2)^{2}} [/tex]
[tex] \frac{5(1) + 3(2)}{(-1)(4)} [/tex]
[tex] \frac{5 + 6}{-4} [/tex]
[tex] \frac{11}{-4} [/tex]
-2.75

5.) x = 8; y = 7
[tex] \frac{5x^{2} + 3xy}{xy^{2} } [/tex]
[tex] \frac{5(8)^{2} + (3)(8)(7)}{8(7)^{2}} [/tex]
[tex] \frac{5(64) + 24(7)}{8(49)} [/tex]
[tex] \frac{320 + 168}{392} [/tex]
[tex] \frac{488}{392} [/tex]
[tex] 1\frac{96}{392} or 1 \frac{12}{49} [/tex]
Evaluate means like find the value given a certain amount. Ex:
1.x=-2; y=-2
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
Sustitute
[tex]\frac{5(-2)^2+3(-2)(-2)}{-2(-2)^2}[/tex]
[tex]\frac{20+12}{-8}[/tex]
Add like terms
[tex]\frac{32}{-8}[/tex]
Divide:
=-4

2.x=1; y=-1
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
Substitute
[tex]\frac{5(1)^2+3(1)(-1)}{1(-1)^2}[/tex]
[tex]\frac{5-3}{1}[/tex]
Add like terms
=2

3.x=-2; y=-1
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
Substitute
[tex]\frac{5(-2)^2+3(-2)(-1)}{-2(-1)^2}[/tex]
[tex]\frac{20+6}{-2}[/tex]
Add like terms
[tex]\frac{26}{-2}[/tex]
Divide
=-13

4.x=-1; y=-2
[tex]\frac{5x^2+3xy}{xy^2}[/tex]
[tex]\frac{5(-1)^2+3(-1)(-2)}{-1(-2)^2}[/tex]
[tex]\frac{5+6}{-4}[/tex]
Add like terms
[tex]\frac{11}{-4}[/tex]
Divide
=-11/4 or -2.75

5.x=8; y=7
Substitute:
[tex]\frac{5(8)^2+3(8)(7)}{7(8)^2}[/tex]
[tex]\frac{320+168}{448}[/tex]
Add like terms
[tex]\frac{488}{488}{/tex]
Divide
=1

Hope this helps =)