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A basketball player is 6 feet 8 inches tall. How far should he stand from a light which is 15 feet above ground, in order to cast a shadow of 25 feet long?

Sagot :

tan α = [tex] \frac{6.67}{25} [/tex]
      α = 14 degree 56' (sorry, there's no degree symbol here)

Let x be the distance of the basketball player from the light
tan 14 degree 56' = [tex] \frac{15}{25 + x} [/tex]
               25 + x = [tex] \frac{15}{tan 14 degree 56'} [/tex]
               25 + x = 56.22
                      x = 56.22 - 25
                      x = 31.22 ft --> answer