IDNStudy.com, ang perpektong platform para sa eksaktong at maaasahang mga sagot. Ang aming mga eksperto ay nagbibigay ng mabilis at eksaktong sagot upang tulungan kang maunawaan at malutas ang anumang problema.

edna paid at least Php,1,200 for a pair of pants and
blouse.The cost of the pair of pants is php.600 more than the cost of
the blouse"






Sagot :

let [tex]x[/tex] be the cost of Blouse

let [tex]x+600[/tex] be the cost of pants

Given:
[tex] C_{tolal} [/tex]

Formula:
[tex] C_{Total} = C_{Pants} + C_{Blouse} [/tex]

Solution:

Cost of Blouse

[tex] C_{T} = (x+600)+(x)[/tex]

[tex] 1200 = (x+600)+(x)[/tex]

[tex]1200=2x+600[/tex]

[tex]1200-600=2x[/tex]

[tex]600=2x[/tex]

[tex] \frac{600}{2} =x[/tex]

[tex]x=Php300.00[/tex]

solve for cost of pants

[tex] C_{Pants} =300+600[/tex]

[tex] C_{pants} = Php900.00[/tex]

Cheking:

[tex] C_{Total} = C_{Pants} + C_{Blouse} [/tex]

[tex] 1200 = 900 + 300 [/tex]

[tex] 1200 = 1200 [/tex]
1200=(600+x)+x
1200=600+2x
1200-600=2x
600=2x
600/2=x
300=x
         

checking:x=300
1200=900=300
1200=1200