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what is the slope of the linear equation y= 13x + 11?

Sagot :

[tex]Slope\ intercept\ form\ given; \\ y=13x+11 \\ \\ x-intercept\ ; \\ Set\ y\ is\ equal\ to\ 0 \\ \\ 0=13x+11 \\ \\ -11=13x \\ \\ \frac{-11}{13}=x \\ \\ \boxed{ (-0.85,0)} \\ \\ y-intercept\ ; \\ Set\ x=0 \\ \\ y=13\cdot\ 0+11 \\ \\ y=11 \\ \\ \boxed{(0,11)} \\ \\ \\ Hope\ it\ Helps :) \\ Domini[/tex]
The formula for the y-intercept is y=mx+b where the coefficient of the x (m) is the slope.

The given equation:
y=13x+11
the m is 13
so the slope is 13/1 where 13 rise and 1 run. Hope this helps =)