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The diagonals of an isosceles trapezoid are represented by 4x-47 and 2x+31. What is the value of x?

Sagot :

If I am not mistaken, the diagonals of an isosceles trapezoid are congruent. Therefore, the equation is:

4x - 47 = 2x + 31
4x - 47 + 47 = 2x + 31 + 47
4x = 2x + 78
4x -2x = 78
2x = 78
x = 39

The value of x is 39.